I know HUBDB basics but I can’t find a solution to this on my own. please help me.
name
no1
no2
no3
no5
no6
no7
xxx
1212
12412
12522
1562
2566
255
yyy
5658
5688
585
zzz
585959
58958
58985
5985699
544455
if you observe the above table, xxx has 7 no’s but yyy have 3no’s.
How to print HUBDB specified columns(in the above example, no’s) only if they are not null for each and every row.
Hello @PrasadKD I would like to invite some top experts to this conversation @dannio @hhawk
@hilton22 any suggestions to @PrasadKD ?
Thank you.
Pam
dannio
February 23, 2022, 1:56am
3
You can add a not_null condition to the query:
e,g if outputting onto a HS page:
{% for row in hubdb_table_rows(<tableId or name>, '&no1__not_null=&no2__not_null=') %}
{% endfor %}
and just add the condition for every column
Great But this one works for the whole list page. I am doing profile pages for each one individually., so for every column, I will use something like this " dynamic_page_hubdb_row.no1". Can you just tell me how to add the above filter for this?
I tried and got the result. Thank you so much