I know HUBDB basics but I can't find a solution to this on my own. please help me.
name | no1 | no2 | no3 | no5 | no6 | no7 |
xxx | 1212 | 12412 | 12522 | 1562 | 2566 | 255 |
yyy | 5658 | 5688 | 585 | |||
zzz | 585959 | 58958 | 58985 | 5985699 | 544455 |
if you observe the above table, xxx has 7 no's but yyy have 3no's.
How to print HUBDB specified columns(in the above example, no's) only if they are not null for each and every row.
Solucionado! Ir para Solução.
fev 22, 2022 8:56 PM
You can add a not_null condition to the query:
e,g if outputting onto a HS page:
{% for row in hubdb_table_rows(<tableId or name>, '&no1__not_null=&no2__not_null=') %}
{% endfor %}
and just add the condition for every column
fev 22, 2022 8:56 PM
You can add a not_null condition to the query:
e,g if outputting onto a HS page:
{% for row in hubdb_table_rows(<tableId or name>, '&no1__not_null=&no2__not_null=') %}
{% endfor %}
and just add the condition for every column
fev 23, 2022 8:49 AM
I tried and got the result. Thank you so much
fev 23, 2022 6:14 AM
Great But this one works for the whole list page. I am doing profile pages for each one individually., so for every column, I will use something like this " dynamic_page_hubdb_row.no1". Can you just tell me how to add the above filter for this?
fev 22, 2022 4:52 PM
Hello @PrasadKD I would like to invite some top experts to this conversation @LPM @hhawk
@hilton22 any suggestions to @PrasadKD ?
Thank you.
Pam
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