le
févr. 22, 2022
2:33 PM
- dernière modification le
févr. 22, 2022
4:28 PM
par
PamCotton
I know HUBDB basics but I can't find a solution to this on my own. please help me.
name | no1 | no2 | no3 | no5 | no6 | no7 |
xxx | 1212 | 12412 | 12522 | 1562 | 2566 | 255 |
yyy | 5658 | 5688 | 585 | |||
zzz | 585959 | 58958 | 58985 | 5985699 | 544455 |
if you observe the above table, xxx has 7 no's but yyy have 3no's.
How to print HUBDB specified columns(in the above example, no's) only if they are not null for each and every row.
Résolu ! Accéder à la solution.
févr. 22, 2022 8:56 PM
You can add a not_null condition to the query:
e,g if outputting onto a HS page:
{% for row in hubdb_table_rows(<tableId or name>, '&no1__not_null=&no2__not_null=') %}
{% endfor %}
and just add the condition for every column
févr. 22, 2022 8:56 PM
You can add a not_null condition to the query:
e,g if outputting onto a HS page:
{% for row in hubdb_table_rows(<tableId or name>, '&no1__not_null=&no2__not_null=') %}
{% endfor %}
and just add the condition for every column
févr. 23, 2022 8:49 AM
I tried and got the result. Thank you so much
févr. 23, 2022 6:14 AM
Great But this one works for the whole list page. I am doing profile pages for each one individually., so for every column, I will use something like this " dynamic_page_hubdb_row.no1". Can you just tell me how to add the above filter for this?
févr. 22, 2022 4:52 PM
Hello @PrasadKD I would like to invite some top experts to this conversation @LPM @hhawk
@hilton22 any suggestions to @PrasadKD ?
Thank you.
Pam
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