Can I integrate the 3rd party API in our HubSpot account to pull the Data?

[sjay]

Hi Team,

I Have a 3rd party API from myNewsDesk. Below is the URL which is in XML format.

Now I wanted to Integrate it into our HubSpot account and I want to pull the results in our HubSpot Webpage.

Is that possible? 

https://www.mynewsdesk.com/services/pressroom/list/zer0r_Gd0PCxImHUtPl4rA/

Thanks,

Sanjay

[sjay]

Hi, @piersg and @dennisedson,

Thanks a lot. Below is the code that is working.

My design is in the form of Listing and detail pages.

For Example https://www.columbusglobal.com/sv/nyheter --> Listing Page

So now I can create a listing page like the above page with the API content. And I will pass the query string value while we click on each item to redirect to the Detail Page.

Here we have two challenges.

1. Is it possible to create User-Friendly Urls/ SEO URLs for each detail page instead of query string?
2. Is it possible to add custom OG/Meta Title and OG/Meta Description in each detail page with these Javascript Variables?
   
   

   <p id="body_text">
   </p>
   <script>
   fetch('https://www.mynewsdesk.com/services/pressroom/list/zer0r_Gd0PCxImHUtPl4rA/')
   .then(response=>response.text())
   .then(data=>{
   const parser = new DOMParser();
   const xmlDOM = parser.parseFromString(data,"text/xml");
   let items = xmlDOM.getElementsByTagName('item');

   for (i = 0, len = items.length; i < len; i++) {
   debugger;
   let item = items[i];
   var News_body= item.getElementsByTagName("body")[0].childNodes[0].nodeValue;
   console.log(item);

   $( "#body_text" ).append( News_body );

   }
   })
   .catch(err=>console.log(err))

   </script>

[piersg · Accepted solution]

Hi @sjay (thanks @dennisedson). You could use JS fetch, like this:

fetch('https://www.mynewsdesk.com/services/pressroom/list/zer0r_Gd0PCxImHUtPl4rA/')
.then(response=>response.text())
.then(data=>{
    const parser = new DOMParser();
    const xmlDOM = parser.parseFromString(data,"text/xml");
    let items = xmlDOM.getElementsByTagName('item');
    for (i = 0, len = items.length; i < len; i++) {
        let item = items[i];
        console.log(item);
    }
})
.catch(err=>console.log(err))

[dennisedson]

@piersg , I thought you were more of an fetch async/await type of guy.  I don't judge. 🙃

[dennisedson]

@piersg ,

Any thoughts for @sjay ?