topic Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap` in APIs & Integrations

Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap`

LSeall — Fri, 18 Nov 2022 10:58:28 GMT

Trying to create a contact with php, using the example code from the hubspot docs but getting the following error -

string(269) "{"status":"error","message":"Invalid input JSON on line 1, column 15: Cannot deserialize value of type `java.util.LinkedHashMap<java.lang.string,java.lang.string>` from Array value (token `JsonToken.START_ARRAY`)","correlationId":"f8d785e4-68c0-4860-b1e6-4ff977c053c1"}"</java.lang.string,java.lang.string>

Here is my code:

$arr = array(
'properties' => array(
array(
'property' => 'email',
'value' => 'apitest@hubspot.com'
)
)
);
$post_json = json_encode($arr);
$accesstoken = "*********************************";

$headers = [
'Content-Type: application/json',
'Authorization: Bearer ' . $accesstoken,
];

$curl = curl_init();
curl_setopt($curl, CURLOPT_HTTPHEADER, $headers);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $post_json);
curl_setopt($curl, CURLOPT_URL, 'https://api.hubapi.com/crm/v3/objects/contacts');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);

$contacts = curl_exec($curl);
curl_close($curl);

var_dump($contacts);

Any ideas?

Re: Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap`

skimura — Sat, 19 Nov 2022 12:04:50 GMT

@LSeall

Hi.

Input parameter format might be wrong.

How about this?

$arr = array( 'properties' => array( 'email' => 'apitest@hubspot.com' ) );

Thanks.

Re: Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap`

EDash — Mon, 21 Nov 2022 01:14:35 GMT

I am having the same problem. My code is nearly identical. I did try with more values in the array though.

(company, email, firstname, lastname, phone, message)

This is code that I'm attempting to migrate from the old API to the newer API (v3) with a private app.

The status code which is returned is: 400

The response is: {"status":"error","message":"Invalid input JSON on line 1, column 15:
Cannot deserialize value of type `java.util.LinkedHashMap<java.lang.String,java.lang.String>`
from Array value (token `JsonToken.START_ARRAY`)",
"correlationId":"32d18bc4-8bdd-41ca-b296-189f768835df"}

I've tried different things, and read through the documentation. I still cannot get this to work. Any guidance is really appreciated!

Re: Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap`

EDash — Mon, 21 Nov 2022 04:45:54 GMT

I understand this better now ... skimura was on the right track.

If you look at the v3 documentation, you'll see the JSON is different than it was in v1.

You need to modify the code used to generate $arr. It no longer has property & value.

Re: Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap`

LSeall — Mon, 21 Nov 2022 09:17:07 GMT

Thanks for this. Changing the array structure sorted it. This is what I used in case it helps others.

$arr = array(
'properties' => array(
'company' => 'Biglytics',
'email' => 'bcooper@biglytics.net',
'firstname' => 'Bryan',
'lastname' => 'Cooper',
'phone' => '(877) 929-0687',
'website' => 'biglytics.net'
)
);
$post_json = json_encode($arr);

Re: Invalid input JSON - Cannot deserialize value of type `java.util.LinkedHashMap`

johnbonds — Wed, 30 Aug 2023 20:36:04 GMT

I believe that the v3 documentation is wrong. It states that updating a contact requires a properties object, not a properties array.